Android字符串和十六進制相互轉化出現的中文亂碼問題

廢話不讀說了，直接給大家貼代碼了，代碼附有注釋，可以說明一切，本文寫的不好，還請見諒。

import java.io.ByteArrayOutputStream;
/**
* Created by Administrator on 2016/2/2.
* -----------16進制和字符串互轉---------
* ------------解決中文亂碼問題---------
*/
public class StringToSixthUtils {
private static String hexString = "0123456789abcdef";
/*
* 將字符串編碼成16進制數字,適用於所有字符（包括中文）
*/
public static String encode(String str) {
//根據默認編碼獲取字節數組
byte[] bytes = str.getBytes();
StringBuilder sb = new StringBuilder(bytes.length * 2);
//將字節數組中每個字節拆解成2位16進制整數
for (int i = 0; i < bytes.length; i++) {
sb.append(hexString.charAt((bytes[i] & 0xf0) >> 4));
sb.append(hexString.charAt((bytes[i] & 0x0f)));
}
return sb.toString();
}
/*
* 將16進制數字解碼成字符串,適用於所有字符（包括中文）
*/
public static String decode(String bytes) {
ByteArrayOutputStream baos = new ByteArrayOutputStream(bytes.length() / 2);
//將每2位16進制整數組裝成一個字節
for (int i = 0; i < bytes.length(); i += 2)
baos.write((hexString.indexOf(bytes.charAt(i)) << 4 | hexString.indexOf(bytes.charAt(i + 1))));
return new String(baos.toByteArray());
}
}

下面給大家分享一段代碼關於16進制字符串和字節數組互相轉換

package com.wpn.net.util; 
public class NumberChange { 
/* 
* 把16進制字符串轉換成字節數組 @param hex @return 
*/ 
public static byte[] hexStringToByte(String hex) { 
int len = (hex.length() / 2); 
byte[] result = new byte[len]; 
char[] achar = hex.toCharArray(); 
for (int i = 0; i < len; i++) { 
int pos = i * 2; 
result[i] = (byte) (toByte(achar[pos]) << 4 | toByte(achar[pos + 1])); 
} 
return result; 
} 
private static byte toByte(char c) { 
byte b = (byte) "0123456789ABCDEF".indexOf(c); 
return b; 
} 
/** 
* 把字節數組轉換成16進制字符串 
* 
* @param bArray 
* @return 
*/ 
public static final String bytesToHexString(byte[] bArray) { 
StringBuffer sb = new StringBuffer(bArray.length); 
String sTemp; 
for (int i = 0; i < bArray.length; i++) { 
sTemp = Integer.toHexString(0xFF & bArray[i]); 
if (sTemp.length() < 2) 
sb.append(0); 
sb.append(sTemp.toUpperCase()); 
} 
return sb.toString(); 
} 
/** 
* @函數功能: BCD碼轉為10進制串(阿拉伯數據) 
* @輸入參數: BCD碼 
* @輸出結果: 10進制串 
*/ 
public static String bcd2Str(byte[] bytes) { 
StringBuffer temp = new StringBuffer(bytes.length * 2); 
for (int i = 0; i < bytes.length; i++) { 
temp.append((byte) ((bytes[i] & 0xf0) >>> 4)); 
temp.append((byte) (bytes[i] & 0x0f)); 
} 
return temp.toString().substring(0, 1).equalsIgnoreCase("0") ? temp.toString().substring(1) : temp.toString(); 
} 
/** 
* @函數功能: 10進制串轉為BCD碼 
* @輸入參數: 10進制串 
* @輸出結果: BCD碼 
*/ 
public static byte[] str2Bcd(String asc) { 
int len = asc.length(); 
int mod = len % 2; 
if (mod != 0) { 
asc = "0" + asc; 
len = asc.length(); 
} 
byte abt[] = new byte[len]; 
if (len >= 2) { 
len = len / 2; 
} 
byte bbt[] = new byte[len]; 
abt = asc.getBytes(); 
int j, k; 
for (int p = 0; p < asc.length() / 2; p++) { 
if ((abt[2 * p] >= '0') && (abt[2 * p] <= '9')) { 
j = abt[2 * p] - '0'; 
} else if ((abt[2 * p] >= 'a') && (abt[2 * p] <= 'z')) { 
j = abt[2 * p] - 'a' + 0x0a; 
} else { 
j = abt[2 * p] - 'A' + 0x0a; 
} 
if ((abt[2 * p + 1] >= '0') && (abt[2 * p + 1] <= '9')) { 
k = abt[2 * p + 1] - '0'; 
} else if ((abt[2 * p + 1] >= 'a') && (abt[2 * p + 1] <= 'z')) { 
k = abt[2 * p + 1] - 'a' + 0x0a; 
} else { 
k = abt[2 * p + 1] - 'A' + 0x0a; 
} 
int a = (j << 4) + k; 
byte b = (byte) a; 
bbt[p] = b; 
} 
return bbt; 
} 
public static void main(String[] arg) { 
/** 
* 68 65 6C 6C 6 F 0A 
* C4 E3 BA C3 
*/ 
String[] str = {"C4", "E3", "BA", "C3"}; 
// String[] str = {"7E","02","04","00","07","10","00","00","00","00","13","08","4F","01","0B","0B","15","10","14","13","44","7E"}; 
byte[] b = new byte[str.length]; 
for(int i=0;i<str.length;i++){ 
b[i] = hexStringToByte(str[i])[0]; 
} 
System.out.println(new String(b)); 
String strC ="你好"; 
String bth=bytesToHexString(strC.getBytes()); 
System.out.println(bth); 
System.out.println(Short.MAX_VALUE); 
System.out.println(Integer.toBinaryString(280)); 
} 
}

以上所述是本文給大家分享的Android字符串和十六進制相互轉化出現的中文亂碼問題的相關內容，希望對大家有所幫助。