Android發送xml數據給服務器的方法

本文實例講述了Android發送xml數據給服務器的方法。分享給大家供大家參考。具體如下：

一、發送xml數據：

public static void main(String[] args) throws Exception {
 String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><videos><video><title>中國</title></video></videos>";
 String path = http://localhost:8083/videoweb/video/manage.do?method=getXML ;
 byte[] entity = xml.getBytes("UTF-8");
 HttpURLConnection conn = (HttpURLConnection) new URL(path).openConnection();
 conn.setConnectTimeout(5000);
 conn.setRequestMethod("POST");
 conn.setDoOutput(true);
 //指定發送的內容類型為xml
 conn.setRequestProperty("Content-Type", "text/xml; charset=UTF-8");
 conn.setRequestProperty("Content-Length", String.valueOf(entity.length));
 OutputStream outStream = conn.getOutputStream();
 outStream.write(entity);
 if(conn.getResponseCode() == 200){
  System.out.println("發送成功");
 }else{
  System.out.println("發送失敗");
 }
}

二、接受xml數據：

public ActionForward getXML(ActionMapping mapping, ActionForm form,
  HttpServletRequest request, HttpServletResponse response)
  throws Exception {
 InputStream inStream = request.getInputStream();
 byte[] data = StreamTool.read(inStream);
 String xml = new String(data, "UTF-8");
 System.out.println(xml);
 return mapping.findForward("result");
}

希望本文所述對大家的Android程序設計有所幫助。